If (x+1)2(x3+x)=Ax+(Bx+c)x2+1 , the sin−1 A+tan−1 B+sec−1 C=
π/2
π/6
0
5π/6
p = (10,7), C = (2,1)
Cp + r , cp – r
If (x+1)2x3+x=Ax+Bx+Cx2+1, then cosec−1(1A)+cot−1(1B)+sec−1C=