If (x+1)2x3+x=Ax+Bx+Cx2+1, then cosec−1(1A)+cot−1(1B)+sec−1C=
5π6
0
π6
π2
A = 1, B = 0, C = 2.
So cosec−11+0+sec−12=π2+0+π3=5π6