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Question

If (x+1)2x3+x=Ax+Bx+Cx2+1, then cosec1(1A)+cot1(1B)+sec1C=


A

5π6

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B

0

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C

π6

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D

π2

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Solution

The correct option is A

5π6


A = 1, B = 0, C = 2.

So cosec11+0+sec12=π2+0+π3=5π6


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