(-1, 0, 1)
(1, 1, -1)
(1, 2, -1)
(0, 1, 0)
−2l=−2m=2n; ∴ (l,m,n) are (1,1,-1).
IfA=⎡⎢⎣201110211⎤⎥⎦ and adjA=⎡⎢⎣12−1xyz−1−22⎤⎥⎦ then (x,y,z)