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Question

If xcos θ=ycos(θ2π3)=zcos(θ+2π3), then x + y + z=


Your Answer
A
1
Your Answer
B
-1
Your Answer
C
None of these

Solution

The correct option is C 0
We have xcos θ=ycos(θ2π3)=zcos(θ+2π3)=k
x=kcos θ,y=kcos(θ2π3),z=kcos(θ+2π3)
x+y+z=k[cos θ+cos(θ2π3)+cos(θ+2π3)]
=k[(0)=0
x+y+z=0.

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