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Question

If xcos θ=ycos(θ2π3)=zcos(θ+2π3), then x + y + z=

A
1
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B
\N
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C
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None of these
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Solution

The correct option is B \N
We have xcos θ=ycos(θ2π3)=zcos(θ+2π3)=k
x=kcos θ,y=kcos(θ2π3),z=kcos(θ+2π3)
x+y+z=k[cos θ+cos(θ2π3)+cos(θ+2π3)]
=k[(0)=0
x+y+z=0.

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