If frequency of a message signal is 4 kHz, then the number of channels that can be accomadated in 80 kHz bandwidth when AM modulation technique is used is

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Solution

The correct option is B 10
When modulated, the bandwidth of the message signal becomes twice i.e., $Δ f = 2 f_{m}$
$= 2 \times 4 k H z = 8 k H z$
So $Δ f \times n = 80 k H z$
$n = 10$

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