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Standard XII

Mathematics

Axiomatic Approach

If from each ...

Question

If from each of the three boxes containing 3 white and 1 black, 2 white and 2 black, 1 white and 3 black balls, one ball is drawn, then the probability that 2 white and 1 black ball will be drawn is

\frac{13}{32}

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\frac{1}{4}

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\frac{1}{32}

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\frac{3}{16}

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Solution

The correct option is A $\frac{13}{32}$
Balls can be drawn in the following way
WWB or WBW or BWW

i.e., Prob = $\frac{3}{4} . \frac{2}{4} . \frac{3}{4} + \frac{3}{4} . \frac{2}{4} . \frac{1}{4} + \frac{1}{4} . \frac{2}{4} . \frac{1}{4} = \frac{13}{32}$

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Similar questions

Q. If one ball is drawn at random from each of three boxes containing 3 white and 1 black, 2 white and 2 black, 1 white and 3 black balls, then the probability that 2 white and 1 black balls will be drawn is
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A box $B 1$ contains $1$ white ball, $3$ red balls and $2$ black balls. Another box $B 2$ contains $2$ white balls, $3$ red balls and $4$ black balls. A third box $B 3$ contains $3$ white balls, $4$ red balls and $5$ black balls. If $1$ ball is drawn from each of the boxes $B 1, B 2$ and $B 3$ the probability that all $3$ drawn balls are of the same color is

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If from each of the three boxes containing 3 white and 1 black, 2 white and 2 black, 1 white and 3 black balls, one ball is drawn, then the probability that 2 white and 1 black ball will be drawn is

The correct option is A 1332Balls can be drawn in the following way WWB or WBW or BWW i.e., Prob = 34.24.34+34.24.14+14.24.14=1332

The correct option is A $\frac{13}{32}$
Balls can be drawn in the following way
WWB or WBW or BWW

i.e., Prob = $\frac{3}{4} . \frac{2}{4} . \frac{3}{4} + \frac{3}{4} . \frac{2}{4} . \frac{1}{4} + \frac{1}{4} . \frac{2}{4} . \frac{1}{4} = \frac{13}{32}$