If from the point P(a, b, c) perpendicular PL, PM be drawn to YOZ and ZOX planes, then the equation of the plane OLM is
A
xa+yb+zc=0
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B
xa−yb+zc=0
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C
xa+yb−zc=0
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D
xa−yb−zc=0
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Solution
The correct option is Cxa+yb−zc=0 Coordinates of L and M are (0, b, c) and (a, 0, c) respectively. ∴ Equation of plane through (0, 0, 0), (0, b, c) and (a, 0, c) is ∣∣
∣∣x−0y−0z−00bca0c∣∣
∣∣=0ie,xa+yb−zc=0