Question

If fully charged battery contains 1.5 L of 5.00 M $H_{2}S{O}_4$ in and 1.5 mol of $H_{2}S{O}_4$ is consumed, concentration of $H_{2}S{O}_4$ after current is drawn is:

• A. 3.50 M
• B. 2.00 M
• C. 4.25 M
• D. 4.00 M

Answer 1

The correct option is D 4.00 M

Molarity of $H_{2}S{O}_4=5M$

$1L{H}_{2}S{O}_4$ has $=5mol$

$\therefore 1.5L{H}_{2}S{O}_4$ has =$5\times 1.5=7.5mol$

$H_{2}S{O}_4$ consumed $=1.5mol$

$H_{2}S{O}_4$left $=7.5-1.5=6mol/1.5L$

Molar concentration of $H_{2}S{O}_4=\frac{6}{1.5}=4mol/L=4M$