If function f(x)=x3+λx2−λx+1 is increasing at x=0 & decreasing at x=1, then find the greatest integer value of λ.
A
−4
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B
2
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C
0
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D
−1
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Solution
The correct option is A−4 f(x)=x3+λx2−λx+1 ⇒f′(x)=3x2+2λx−λ Now for f to be increasing at x=0 and decreasing at x=1 we must have, f′(0)>0 and f′(1)<0 ⇒−λ>0 and 3+2λ−λ<0 ⇒λ<0 and λ<−3 Hence λ<−3 Thus greatest integral value of λ is −4