If $f (x) = |x - 3| and g (x) = f o f (x)$ , then for x > 10, g ' (x) is equal to
(a) 1
(b) −1
(c) 0
(d) none of these

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Solution

(c) 0

$For, x > 10 f (x) = |x - 3| = x - 3 g (x) = f o f (x) = |x - 3| - 3 = x - 3 - 3 = x - 6 ∴ g' (x) = 1$

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