If $g = 10 m / s^{2}$ and the radius of the earth is 6400 km, the first orbital velocity is equal to

8 m / s

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8 k m / s

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9.72 m / s

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8.7 k m / s

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Solution

The correct option is B $8 k m / s$
First orbital velocity is the velocity of the satellite at a distance near to the surface of the earth. Thus $v = \sqrt{(g R)} = \sqrt{(10 X 6400 X 10^{3})} = 8 K m / s$
The correct option is (b)

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If g=10m/s2 and the radius of the earth is 6400 km, the first orbital velocity is equal to

The correct option is B 8km/sFirst orbital velocity is the velocity of the satellite at a distance near to the surface of the earth. Thus v=√(gR)=√(10X6400X103)=8Km/sThe correct option is (b)

If $g = 10 m / s^{2}$ and the radius of the earth is 6400 km, the first orbital velocity is equal to

The correct option is B $8 k m / s$
First orbital velocity is the velocity of the satellite at a distance near to the surface of the earth. Thus $v = \sqrt{(g R)} = \sqrt{(10 X 6400 X 10^{3})} = 8 K m / s$
The correct option is (b)