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Question

If g:[2:2]R where g(x)=x3+tanx+[x2+1p] is a odd function then the value of parametric P is where [.] denotes the Greatest integer function.

A
-5<P<5
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B
P<5
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C
P>5
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D
None of these
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Solution

The correct option is C P>5

g(x)=x3+tanx+[x2+1p]

g(x)=(x)3+tan(x)+[(x)2+1p]

g(x)=x3tanx+[x2+1p]

g(x)+g(x)=0 because g(x) is a odd function

x3+tanx+[x2+1p]x3tanx+[x2+1p]=0

2[(x2+1)p]=0

0x2+1p<1 because x[2,2]

05p<1p>5.


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