Question

$IfG={\int }_2^{x{}^2}\frac{1}{ln(1+t^2)}dt$ then G is a function of "t" .

• A. True
• B. False

Answer 1

The correct option is B False

We can see that the given function G is written in terms of integral. This integral has limits of “t” since dt is the infinitesimally small. So, when we’ll integrate this integral and put the limits at all the places where t is present, “t” will be replaced by limits. Therefore there will not “t” in the expression. And on putting the limits we’ll have “x” as the variable.