The given grammer is S→SaS∣aSb∣bSa∣SS∣ϵ
generates all strings with equal number of 'a' and 'b'
Now, S→SaS can only generate strings where 'a' is more than 'b' since on left and right of 'a' in SaS, S will have only strings with na=nborna>nb.
So, option (d) "babba" which is a string with nb>na is not possible to generate by the given grammer.