Question

If $g$ is acceleration due to gravity, then the vertical distance traveled by a projectile in time t is equal to

• A. $\frac{1}{2}g{t}^2$
• B. $g{t}^2$
• C. $\frac{3}{4}g{t}^2$
• D. none of these

Answer 1

The correct option is A

$\frac{1}{2}g{t}^2$

STEP 1: Given data

Acceleration due to gravity $\left(a\right)$ $=g$

Vertical distance covered $=s$

Time taken $=t$

STEP 2:Finding vertical distance S

$s=ut+\frac{1}{2}a{t}^2$ ,

we get

$$\begin{gathered} s=0+\frac{1}{2}g{t}^2 \\ s=\frac{1}{2}g{t}^2 \end{gathered}$$

Therefore, the vertical distance travelled by a projectile in time $t$ is equal to $\frac{1}{2}g{t}^2$.

Hence, option A is correct.