Question

If $g$ is the acceleration due to gravity and $\lambda$ is wavelength then which physical quantity does $\sqrt{\lambda g}$ present?.

Answer 1

Given that,

Acceleration due to gravity $=g$

Wave length $=\lambda$

Now, the units is

$\lambda =m$

$g=m/s^2$

Now, put the unit

$\sqrt{\lambda g}=\sqrt{m\times m/s^2}$

$\sqrt{\lambda g}=\sqrt{m^2/s^2}$

$\sqrt{\lambda g}=m/s$

We know that,

$m/s=speed$

Hence, the physical quantity is speed