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Variation of g (Acceleration Due to Gravity)

If g is the a...

Question

If g is the acceleration due to gravity on the surface of the earth, it's value at a height equal to triple the radius of earth is (assuming the earth to be a perfect sphere)

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Solution

Value of acceleration due to gravity at height comparable with radius of earth is given by

g' = g(R/(R+h))^2

In problem h = 3R

g' = g(R/4R)^2 = g/16

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