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Question

If g(x)=xxloge(ex)dx then g(π) equals

A
πlogeπ
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B
ππloge(eπ)
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C
ππloge(π)
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D
ππ
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Solution

The correct option is D ππ
g(x)=xx(1+logex)dx=d(xx)g(x)=xxg(π)=ππ

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