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Question
If g(x)=−√25−x2, find Ltx→1g(x)−g(1)x−1
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Solution
g(x)=−√25−x2
g(1)=−√25−1=−√24=−2√6
limx→1g(x)−g(1)x−1
=limx→1−√25−x2+2√6x−1 (00form)
=limx→1x√25−x2(using L'hospital rule)
=1√24
=12√16
g(x)=−√25−x2
g(1)=−√25−1=−√24=−2√6
limx→1g(x)−g(1)x−1
=limx→1−√25−x2+2√6x−1 (00form)
=limx→1x√25−x2(using L'hospital rule)
=1√24
=12√16
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