Question

If $\gamma$ be the ratio of molar heat capacities of an ideal gas, then degree of freedom for the molecules of gas is :

• A. $\frac{25}{2}(\gamma -1)$
• B. $\frac{3\gamma -1}{2\gamma -1}$
• C. $\frac{2}{\gamma -1}$
• D. $\frac{\gamma }{2}(\gamma -1)$

Answer 1

The correct option is C $\frac{2}{\gamma -1}$

We know that,
$\gamma =1+\frac{2}{f}$
Where, $f=$ degree of freedom
$\gamma =\frac{C_p}{C_V}$
$\Rightarrow \frac{2}{f}=\gamma -1$
$\therefore f=\frac{2}{\gamma -1}$