If $γ$ be the ratio of molar heat capacity of an ideal gas, then degree of freedom for the molecule of gas is

\frac{25}{2} (γ - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3 γ - 1}{2 γ - 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{γ - 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{γ}{2} (γ - 1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{2}{γ - 1}$
We know that,
$γ = 1 + \frac{2}{f}$
Where $f =$ degree of freedom
$γ = \frac{C_{p}}{C_{V}}$
$\Rightarrow \frac{2}{f} = γ - 1$
$∴ f = \frac{2}{γ - 1}$

Suggest Corrections

Similar questions

=

T = k V

γ

\frac{C_{P}}{C_{V}}

P T = c o n s t a n t i s 5 R

Join BYJU'S Learning Program