If γ,δ are the roots of x2−3x+a=0,aϵR, and γ<1<δ then
A
aϵ(−∞,2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
aϵ(−∞,94)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
aϵ(2,94)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is Aaϵ(−∞,2)
Let γandδ be roots of the equation x2−3x+a=0. The corresponding polynomial of this equation is f(x)=x2−3x+a
From the figure, D>0⇒9−4a>0⇒a<94 f(1)<0⇒1−3+a<0⇒a<2
On taking intersection we get, aϵ(−∞,2)