Question

If $\gamma$ is the ratio of specific heats and $R$ is the universal gas constant, then the molar specific heat at constant volume $C_v$ is given by

• A. $\gamma R$
• B. $\frac{(\gamma -1)R}{\gamma }$
• C. $\frac{R}{\gamma -1}$
• D. $\frac{\gamma R}{\gamma -1}$

Answer 1

Answer: (C)

$\frac{R}{\gamma -1}$

$C_p-C_v=R$

$\frac{C_p}{Cv}-1=\frac{R}{C_v}$

$\gamma -1=\frac{R}{C_v}$

$C_v=\frac{R}{\gamma -1}$