Question

If, getting a number greater than $4$ on a fair die is considered a success, then the variance of the distribution of success on tossing a die five times is

• A. $\frac{5}{4}$
• B. $\frac{10}{9}$
• C. $\frac{2}{3}$
• D. $\frac{1}{3}$

Answer 1

The correct option is B $\frac{10}{9}$

The given event will follow binomial distribution,
where $n=5$,
$p=\frac{2}{6}=\frac{1}{3}$
and $q=1-\frac{1}{3}=\frac{2}{3}$
So, variance $=npq=\frac{10}{9}$