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Question

If given constraints are 5x+4y2,x6,y7, then the maximum value of the function z=x+2y is

A
13
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B
14
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C
15
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D
20
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Solution

The correct option is D 20
Given,
z=x+2y
and 5x+4y=2
x25+y12=1
At point A(25,0),z=25+0=25
At point B(6,0),z=6+0=6
At point C(6,7),z=6+14=20
At point D(0,7),z=0+2(7)=14
At point E(0,12),z=0+2(12)=1
The maximum value of z is 20.
1047034_462252_ans_e2bf80a8871d483ca9a7ed7c0e27d29b.png

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