If $H_{2}, C H_{4}, C O_{2}$ and $N H_{3}$ gases are adsorbed by 1 gram charcoal at 290 k temperature, then decreasing order of their volume is:

C O_{2} > N H_{3} > H_{2} > C H_{4}

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C H_{4} > C O_{2} > N H_{3} > H_{2}

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H_{2} > C H_{4} > C O_{2} > N H_{3}

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N H_{3} > C O_{2} > C H_{4} > H_{2}

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Solution

The correct option is D $N H_{3} > C O_{2} > C H_{4} > H_{2}$
H₂ 4.7 cc per gm
CH4 16.2 cc per gm
CO₂ 48 cc per gm
NH₃ 181 cc per gm.
NH3>CO2>CH4>H2

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Similar questions

The volumes of gases $H_{2}, C H_{4}, C O_{2} a n d N H_{3}$ absorbed by 1 g of charcoal at 288 K are in the order:

The volume of gases $N H_{3}$ , $C O_{2}$ and $C H_{4}$ adsorbed by one gram of charcoal at 298 K are in

H_{2}, {C H}_{4}, {C O}_{2}

{N H}_{3}

1 g

288 K

The volumes of gases $H_{2}, C H_{4}, C O_{2} a n d N H_{3}$ absorbed by 1 g of charcoal at 288 K are in the order:

H_{2}, C H_{4}, C O_{2}

N H_{3}

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