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Standard XII

Chemistry

De Broglie's Hypothesis

If H2, He, ...

Question

If $H_{2}, H e, O_{2}$ and $N_{2}$ tarvel with same velocity then the longest de-Brogile wavelength should be associated with:

H_{2}

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H e

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O_{2}

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N_{2}

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Solution

The correct option is C $H_{2}$
$λ = h / m v$ so wavelength varies inversely to the mass.
Thus, smaller mass have larger wavelength and $H_{2}$ have smaller mass than $H e, O_{2}, N_{2}$ so it has greater wavelength.

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Similar questions

Q. If

H_{2}

, He,

O_{2}

N_{2}

travel with same velocity then the longest de-Broglie wavelength should be associated with:

Q. If

H_{2}

He,

O_{2}

N_{2}

travel with the same velocity then the longest de-broglie wavelength should be associated with

Q. Gases

H_{2} H e O_{2} N_{2}

Critical temperature(K) 33.2 5.3 154.3 126

From the above data what whould be the order of liquefaction of these gases?
Start writing the order from the gas liquefying first.

Q. At

S T P

the order of mean square velocity of molecules of

H_{2}, N_{2}, O_{2}

and

H B r

is-

Gases posses charcteristic critical temperature which depends upo the magnitude of intermolecular forces between the particles. Following are the critical temperatures of some gases.

$\begin{matrix} G a s e s & H_{2} & H e & O_{2} & N_{2} C r i t i c a l t e m p e r a t u r e i n K e l v i n & 33.2 & 5.3 & 154.3 & 126 \end{matrix}$

From the above data what would be the order of liquefaction of these gases? Start writing the order from the gas liquefying first

(a) $H_{2}, H e, O_{2}, N_{2}$ (b) $H e, O_{2}, H_{2}, N_{2}$

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If H2,He,O2 and N2 tarvel with same velocity then the longest de-Brogile wavelength should be associated with:

The correct option is C H2λ=h/mv so wavelength varies inversely to the mass. Thus, smaller mass have larger wavelength and H2 have smaller mass than He,O2,N2 so it has greater wavelength.

If $H_{2}, H e, O_{2}$ and $N_{2}$ tarvel with same velocity then the longest de-Brogile wavelength should be associated with:

The correct option is C $H_{2}$
$λ = h / m v$ so wavelength varies inversely to the mass.
Thus, smaller mass have larger wavelength and $H_{2}$ have smaller mass than $H e, O_{2}, N_{2}$ so it has greater wavelength.