If
H=⎡⎢⎣123231312⎤⎥⎦,G=⎡⎢⎣26−100−482−84⎤⎥⎦,
then find
3H−12G.
Given:
H=⎡⎢⎣123231312⎤⎥⎦,G=⎡⎢⎣26−100−482−84⎤⎥⎦ [0.5 Marks]
3H=⎡⎢⎣3×13×23×33×23×33×13×33×13×2⎤⎥⎦=⎡⎢⎣369693936⎤⎥⎦ [0.5 Marks]
12G=⎡⎢⎣2÷26÷2−10÷20÷2−4÷28÷22÷2−8÷24÷2⎤⎥⎦=⎡⎢⎣13−50−241−42⎤⎥⎦ [1 Mark]
3H−12G=⎡⎢⎣2314611−1874⎤⎥⎦ [1 Mark]