If H.C.F of $x^{3} y^{4} z^{2}$ and $x^{6} y^{8} z^{4}$ is 'a' and H.C.F of $x^{5} y^{6} z^{3}$ and $x^{6} y^{7} z^{4}$ is 'b' then $\frac{a}{b}$ = .

x^{2} y^{4} z^{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{- 2} y^{- 2} z^{- 1}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

x^{- 3} y^{- 4} z^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

x^{3} y^{4} z^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $x^{- 2} y^{- 2} z^{- 1}$
HCF of $x^{3} y^{4} z^{2}$ and $x^{6} y^{8} z^{4}$ is $x^{3} y^{4} z^{2}$ .
So, $a = x^{3} y^{4} z^{2}$

HCF of $x^{5} y^{6} z^{3}$ and $x^{6} y^{7} z^{4}$ is $x^{5} y^{6} z^{3}$ .
So, $b = x^{5} y^{6} z^{3}$

$⟹$ $\frac{a}{b} = x^{- 2} y^{- 2} z^{- 1}$

Suggest Corrections

Similar questions

If H.C.F of $x^{3} y^{4} z^{2}$ , $x^{6} y^{8} z^{4}$ is 'a' and H.C.F of $x^{5} y^{6} z^{3}$ , $x^{6} y^{7} z^{4}$ is 'b' then $a / b =$ ___

H.C.F of $x^{3} y^{4} z^{2}$ and $x^{6} y^{8} z^{4}$ is 'a' and H.C.F of $x^{5} y^{6} z^{3}$ and $x^{6} y^{7} z^{4}$ is 'b'. What is $\frac{a}{b}$

A

B

24

C

D

56,

A, B, C

D

=

=

=

\times

=

Join BYJU'S Learning Program