If $h$ is Planck's constant is $S I$ system, the momentum of a photon of wavelength $0.01 ˚ A$ is :

10^{- 2} h

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h

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10^{2} h

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10^{12} h

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Solution

The correct option is C $10^{2} h$
$λ = \frac{h}{p}$
$p = \frac{h}{λ}$
$p = \frac{h}{10^{- 2}} = 10^{2} h$

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If h is Planck's constant is SI system, the momentum of a photon of wavelength 0.01 ˚A is :

The correct option is C 102 hλ=hpp=hλp=h10−2=102h

If $h$ is Planck's constant is $S I$ system, the momentum of a photon of wavelength $0.01 ˚ A$ is :

The correct option is C $10^{2} h$
$λ = \frac{h}{p}$
$p = \frac{h}{λ}$
$p = \frac{h}{10^{- 2}} = 10^{2} h$