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Standard XII

Physics

Electric Field

If h is Plank...

Question

If h is Plank’s constant and e is charge, then dimensions of resistance are same as

\frac{h}{e}

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\frac{h^{2}}{e}

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\frac{h}{e^{2}}

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\frac{h^{2}}{e^{2}}

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Solution

The correct option is C $\frac{h}{e^{2}}$
By verifying options
$\frac{h}{e^{2}} = \frac{j o u l e - s e c o n d}{C . C} = \frac{v o l t - C - s}{C . C} = \frac{v o l t}{a m p e r e} = o h m$

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If h is Plank’s constant and e is charge, then dimensions of resistance are same as

The correct option is C he2By verifying options he2=joule−secondC.C=volt−C−sC.C=voltampere=ohm

The correct option is C $\frac{h}{e^{2}}$
By verifying options
$\frac{h}{e^{2}} = \frac{j o u l e - s e c o n d}{C . C} = \frac{v o l t - C - s}{C . C} = \frac{v o l t}{a m p e r e} = o h m$