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Question

If h,S,V be the height, curved surface area and volume of a cone respectively, then (3πVh3S2h2+9V2) is equal to:

A
8
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B
0
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C
4π
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D
32π2
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Solution

The correct option is B 0
3πVh2S2h3+9V2=3π×13πr2h×h3(πrr2+h2)2h2+9×(13πr2h)2
=π2r2h4h2(π2r2(r2+h2))+9×19π2r4h2=π2r2h4π2r4h2π2r2h4+π2r4h2
3πVh3S2h2+9V2=0

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