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Question

If h(x)=x1sin4tdt, then h(x+π) equals

A
h(x)+h(π)
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B
h(x)h(π)
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C
h(x)h(π)
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D
h(x)/h(π)
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Solution

The correct option is B h(x)+h(π)
h(x+π)=h(π)+I
where I=x+ππsin4tdt
Substitute t=θ+π so that
I=x0(sin(π+θ))4dθ
=x0(sinθ)4dθ=h(x)
h(x+π)=h(π)+h(x)

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