Question

If $h\left(x\right)=x^2-2$, then the value of $\frac{1}{2}h\left(\frac{1}{2}\right)$ is:

• A. $0$
• B. $1$
• C. $-\frac{7}{8}$
• D. $\frac{7}{8}$

Answer 1

Answer: (C)

$-\frac{7}{8}$

Given, $h\left(x\right)=x^2-2$

$\therefore h\left(\frac{1}{2}\right)={\left(\frac{1}{2}\right)}^2-2=\frac{1}{4}-2=\frac{-7}{4}$

$\therefore \frac{1}{2}h\left(\frac{1}{2}\right)=\frac{1}{2}\times \frac{-7}{4}=\frac{-7}{8}$