Question

If HCF of $210$ and $55$ is of the form $\left(210\right)\left(5\right)+55y$, then the value of $y$ is :

• A. $-19$
• B. $-18$
• C. $5$
• D. $55$

Answer 1

The correct option is A $-19$

HCF of 210 and 55 is 5

Given HCF = $\left(210\right)\left(5\right)+55y$

$5=\left(210\right)\left(5\right)+55y$

$55y$=$-1045$

On solving this equation we get $y=-19$

So, correct answer will be option A