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Question

If He (g) is bubbled through the water at 298 K, how many millimoles of He (g) would dissolve in one litre of water?
Assume that He (g) exerts a partial pressure of 0.5 bar
Take Henry's Law constant for He (g) at 298 K as 145 kBar

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Solution

The solubility of gas is realted to the mole fraction in aqueous solution. The mole fraction of the gas in solution is calculated by applying Henry's Law
Thus :

According to Henry's law :
χHe=pHeKH=0.5 bar145000 bar=3.45×106

As 1 litre of water contains 55.55 mol of it, therefore if n represents number of moles of He (g) in solution
χHe=nn+55.55
Since , n<<55.55n55.55=3.45×106n=1.91×104 moln=1.91×104×1000 mmoln=0.191 mmol

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