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Question

If heat of dissociation of CHCl2COOH is 0.7 kcal/mol, then H for the reaction:
CHCl2COOH+KOHCHCl2COOK+H2O

A
- 13 kcal
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B
+13 kcal
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C
-14.4 kcal
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D
-13.7 kcal
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Solution

The correct option is A - 13 kcal
H++OHH2O(l) H=13.7 kcal ...(i)
CHCl2COOHCHCl2COO+H+ H=0.7 kcal ...(ii)
CHCl2COOH+OHCHCl2COO+H2O(l) H=?
Adding equation (i) and (ii) H=13 kcal.

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