If heat of dissociation of CHCl2COOH is 0.7 kcal/mol, then △H for the reaction: CHCl2COOH+KOH→CHCl2COOK+H2O
A
- 13 kcal
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B
+13 kcal
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C
-14.4 kcal
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D
-13.7 kcal
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Solution
The correct option is A - 13 kcal H++OH−→H2O(l)△H=−13.7kcal ...(i) CHCl2COOH→CHCl2COO−+H+△H=0.7kcal ...(ii) CHCl2COOH+OH−→CHCl2COO−+H2O(l)△H=?
Adding equation (i) and (ii) △H=−13kcal.