If heat of dissociation of CHCl2COOH is 0.7 kcal/mole then ΔH for the reaction:
CHCl2COOH + KOH → CHCl2COOK + H2O
-13 kcal
H+ + OH− → H2O(l)
ΔH = −13.7 kcal........(i)
CHCl2COOH → CHCl2COO− + H+
ΔH = 0.7 kcal........(ii)
CHCl2COOH + OH− → CHCl2COO− + H2O(l)
ΔH = ?
Adding equation (i) and (ii) ΔH = = 13Kcal.