If helium and methane are allowed to diffuse out of the container under the similar conditions of temperature and pressure, then the ration of rate of diffusion of helium to methane is:

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Solution

The correct option is C 2
$Rate of diffusion \propto \frac{1}{\sqrt{Molecular weight}}$
$\frac{Rate of diffusion of Helium}{Rate of diffusion of methane} = \sqrt{\frac{16}{4}} = \sqrt{4} = 2$

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If helium and methane are allowed to diffuse out of the container under the similar conditions of temperature and pressure, then the ration of rate of diffusion of helium to methane is:

The correct option is C 2Rate of diffusion∝1√Molecular weightRate of diffusion of HeliumRate of diffusion of methane=√164=√4=2

The correct option is C 2
$Rate of diffusion \propto \frac{1}{\sqrt{Molecular weight}}$
$\frac{Rate of diffusion of Helium}{Rate of diffusion of methane} = \sqrt{\frac{16}{4}} = \sqrt{4} = 2$