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Question

If Hund's rule violated, then how many unpaired electron(s) is/are present in [Cr(NH3)6]3+ complex ion?

A
1
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B
2
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C
3
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D
None
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Solution

The correct option is A 1
[Cr(NH3)6]3+
Cr is in +3 oxidation state.
Cr3+[Ar]3d3
NH3 is a strong field ligand so it will pair the electron. Then only one unpaired electron will remain in 3d orbital.

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