Question

If hydrogen atom is its ground state absorbs $10.2eV$ of energy. The orbital angular momentum is increase by

• A. $1.05\times {10}^{-34}J/s$
• B. $3.16\times {10}^{-34}J/s$
• C. $2.11\times {10}^{-34}J/s$
• D. $4.22\times {10}^{-34}J/s$

Answer 1

The correct option is A $1.05\times {10}^{-34}J/s$

Electron goes to its first excited state $(n=2)$ from ground state $(n=1)$ after absorbing $10.2eV$ energy
$\therefore$ Increase in momentum $=\frac{h}{2\pi }$
$=\frac{6.6\times {10}^{-34}}{6.28}$
$=1.05\times {10}^{-34}J-s$