If $I_{1}$ and $I_{2}$ be the size of the images respectively for the two positions of lens in the displacement method, then the size of the object is given by

I_{1} / I_{2}

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I_{1} \times I_{2}

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\sqrt{I_{1} \times I_{2}}

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\sqrt{I_{1} / I_{2}}

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Solution

The correct option is B $I_{1} \times I_{2}$
As we know,
$\frac{I_{1}}{O} = \frac{v}{u}$ and $\frac{I_{2}}{O} = \frac{u}{v} \Rightarrow O^{2} = I_{1} I_{2}$

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Similar questions

Now what should be the correct relation between $I_{1}$ , $I_{2}$ and $I_{3}$ .

If $I_{1} = \int_{0}^{\frac{π}{2}} x s i n x d x & I_{2} = \int_{0}^{\frac{π}{2}} x c o s x d x$ , then which of the following is true?

I_{1}

I_{2}

x

I_{1} = π / 2 \int 0 cos (sin x) d x; I_{2} = π / 2 \int 0 sin (cos x) d x

I_{3} = π / 2 \int 0 cos x d x,

I_{1} = 1 \int 0 e^{- x} {cos}^{2} x d x

I_{2} = 1 \int 0 e^{- x^{2}} {cos}^{2} x d x

I_{3} = 1 \int 0 e^{- x^{3}} d x

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