wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If I1=102x2dx, I2=102x3dx, I3=212x2dx and I4=412x3dx

then which of the following is true?

A
I1>I2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
I2>I1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
I3>I4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
I3=I4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A I1>I2
For 0<x<1, x2>x3 2x2>2x3 and for 1<x<2, x3>x2 2x3>2x2

i.e. 2x2<2x3 I3<I4

As 2x2>2x3 102x2dx>102x3dx

I1>I2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon