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Byju's Answer
Standard XII
Mathematics
Arithmetic Progression
If I1=∫012x...
Question
If
I
1
=
∫
1
0
2
x
2
d
x
,
I
2
=
∫
1
0
2
x
3
d
x
,
I
3
=
∫
2
1
2
x
2
d
x
and
I
4
=
∫
4
1
2
x
3
d
x
then which of the following is true?
A
I
1
>
I
2
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B
I
2
>
I
1
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C
I
3
>
I
4
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D
I
3
=
I
4
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Solution
The correct option is
A
I
1
>
I
2
For
0
<
x
<
1
,
x
2
>
x
3
∴
2
x
2
>
2
x
3
and for
1
<
x
<
2
,
x
3
>
x
2
∴
2
x
3
>
2
x
2
i.e.
2
x
2
<
2
x
3
⇒
I
3
<
I
4
As
2
x
2
>
2
x
3
∴
∫
1
0
2
x
2
d
x
>
∫
1
0
2
x
3
d
x
∴
I
1
>
I
2
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0
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Q.
If
I
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1
0
2
x
3
d
x
,
I
2
=
∫
1
0
2
x
2
d
x
,
I
3
=
∫
2
1
2
x
2
d
x
and
I
4
=
∫
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1
2
x
3
d
x
, then
Q.
If
I
1
=
∫
1
0
2
x
2
d
x
,
I
2
=
∫
1
0
2
x
3
d
x
,
I
3
=
∫
2
1
2
x
2
d
x
and
I
4
=
∫
2
1
2
x
3
d
x
then
Q.
lf
I
1
=
∫
1
0
2
x
2
d
x
,
I
2
=
∫
1
0
2
x
3
d
x
,
I
3
=
∫
2
1
2
x
2
d
x
and
I
4
=
∫
2
1
2
x
3
d
x
, then
Q.
If
I
1
=
∫
1
0
2
x
2
d
x
,
I
2
=
∫
1
0
2
x
3
d
x
I
3
=
∫
2
1
2
x
2
d
x
and
I
4
=
∫
2
1
2
x
3
d
x
then which of the following is correct?
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