Geometric Interpretation of Def.Int as Limit of Sum
If I1=∫0π / 2...
Question
If I1=π/2∫0cos(sinx)dx,I2=π/2∫0sin(cosx)dx and I3=π/2∫0cosxdx, then
A
I1>I3>I2
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B
I3>I1>I2
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C
I11>I2>I3
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D
I3>I2>I1
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Solution
The correct option is AI1>I3>I2 For x∈(0,π2),
we know that ⇒cosx>sin(cosx)[∵f(x)=cosx−sin(cosx)is decreasing in given interval]⇒I3>I2
Also, x>sinx⇒cos(sinx)>cosx[∵cosx is decreasing function]⇒I1>I3∴I1>I3>I2