If I1-01 2x2 dx- I2-01 2x3dx- I3 - -12 2x2dx and I4-12 2x3 dx then

I_1 gt;I_2 (∵ 2^x^2 gt;2^x^2 if 0≤ x≤ 1) I_3 lt;I_4(∵ 2^x^3 gt; 2^x^2 if x gt;1) ...

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Property 4

If I1=∫01 2x2...

Question

$I f I_{1} = \int_{0}^{1} 2^{x^{2}} d x, I_{2} = \int_{0}^{1} 2^{x^{3}} d x, I_{3} = \int_{1}^{2} 2^{x^{2}} d x a n d I_{4} = \int_{1}^{2} 2 x^{3} d x t h e n$

I_{3} > I_{4}

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I_{3} = I_{4}

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I_{1} > I_{2}

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I_{2} > I_{1}

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Solution

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Similar questions

I f I_{1} = \int_{0}^{1} 2^{x^{2}} d x, I_{2} = \int_{0}^{1} 2^{x^{3}} d x, I_{3} = \int_{1}^{2} 2^{x^{2}} d x a n d I_{4} = \int_{1}^{2} 2 x^{3} d x t h e n

I_{1} = \int_{0}^{1} 2^{x^{2}}

I_{2} = \int_{0}^{1} 2^{x^{3}}

I_{3} = \int_{1}^{2} 2^{x^{2}}

I_{4} = \int_{1}^{2} 2^{x^{3}}

I_{1} = \int_{0}^{1} 2^{x^{3}} d x, I_{2} = \int_{0}^{1} 2^{x^{2}} d x, I_{3} = \int_{1}^{2} 2^{x^{2}} d x

I_{4} = \int_{1}^{2} 2^{x^{3}} d x

I_{1} = \int_{0}^{1} 2^{x^{2}} d x, I_{2} = \int_{0}^{1} 2^{x^{3}} d x, I_{3} = \int_{1}^{2} 2^{x^{2}} d x

I_{4} = \int_{1}^{2} 2^{x^{3}} d x

I f I_{1} = \int_{0}^{1} 2^{x^{2}} d x, I_{2} = \int_{0}^{1} 2^{x^{3}} d x, I_{3} = \int_{1}^{2} 2^{x^{2}} d x a n d I_{4} = \int_{1}^{2} 2 x^{3} d x t h e n

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