If i 2-1- then the value of - n -1200 i n isA- 50B- -50C- 0D- 100

The correct option is C 0 ∑_n=1^200 i^n = i + i^2 + i^3 + .... + i^200 = i(1 i^200)/1 i (since G.P) = i(1 1)/1 i = 0 . ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Complex Numbers

if i 2=-1, th...

Question

if $i^{2} = - 1$ , then the value of $200 \sum n = 1 i^{n}$ is

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-50

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

f (n) = [\frac{1}{2} + \frac{n}{100}]

\sum_{n = 1}^{100} f (n)

If $x^{51}$ +51 is divided by x + 1, the remainder is

a = 1 + i^{2} + i^{4} + \dots + i^{2 n}

b = {cos}^{- 1} (∣ ∣ ∣ \frac{1}{1 + i} ∣ ∣ ∣)

i = \sqrt{- 1}

tan (\frac{b}{a})

f (x) = 1 + x + x^{2} + \dots + x^{1000}

f^{'} (- 1)

x,y are positive and x³y² = 6. The least value of is 4x + 3y is

Join BYJU'S Learning Program