If i 2-1- then the value of - n -1200 i n isA- 50B- -50C- 0D- 100

The correct option is C 0 ∑_n=1^200 i^n = i + i^2 + i^3 + .... + i^200 = i(1 i^200)/1 i (since G.P) = i(1 1)/1 i = 0 . ...

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Complex Numbers

if i 2=-1, th...

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if $i^{2} = - 1$ , then the value of $200 \sum n = 1 i^{n}$ is

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-50

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100

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