If I- 2-ab-x-x-a-b-x dx- then I equals

The correct option is A b a I=2∫ _ a ^ b √( x ) #160;√( x ) +√( a+b x ) #160; dx #160; ...(1)Using integration property #160; I=2∫ _ a ...

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Special Integrals - 1

If I= 2∫ab√...

Question

If $I = 2 \int_{a}^{b} \frac{\sqrt{x}}{\sqrt{x} + \sqrt{a + b - x}} d x$ , then $I$ equals

b - a

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\sqrt{b} - \sqrt{a}

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\frac{1}{2} {(b - a)}^{2}

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0

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b > a,

I = \int_{a}^{b} \sqrt{\frac{x - a}{b - x}} d x,

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\int_{a}^{b} \frac{| x |}{x} d x =

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