If I add a 2 digit number and the number formed by swapping digits, the resultant number is surely divisible by ___

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Solution

Let a be the tenths and b be the units digit of the original number. Therefore the sum will be:
(10a + b) + (10b + a) = 11a + 11b

= 11 (a + b)
Which is divisible by 11.

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If I add a 2 digit number and the number formed by swapping digits, the resultant number is surely divisible by ___

Let a be the tenths and b be the units digit of the original number. Therefore the sum will be: (10a + b) + (10b + a) = 11a + 11b = 11 (a + b) Which is divisible by 11.

Let a be the tenths and b be the units digit of the original number. Therefore the sum will be:
(10a + b) + (10b + a) = 11a + 11b

= 11 (a + b)
Which is divisible by 11.